document.write( "Question 26824: A bag contains 6 red marbles, 9 blue marbles, and 5 green marbles. You withdrew one marble,replace it, and then withdraw another marble. what is the probability that you do NOT pick two green marbles? \n" ); document.write( "
Algebra.Com's Answer #14600 by venugopalramana(3286)\"\" \"About 
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A bag contains 6 red marbles, 9 blue marbles, and 5 green marbles. You withdrew one marble,replace it, and then withdraw another marble. what is the probability that you do NOT pick two green marbles?
\n" ); document.write( "in such problems it is easier to find probability of an event happening and subtract it from total probability of 1 to get probability of event not happening.
\n" ); document.write( "SO LET US CONSIDER PROBABILITY OF DRAWING 2 GREEN MARBLES.
\n" ); document.write( "THERE ARE 6 RED+9 BLUE+5 GREEN MARBLES=20 MARBLES.
\n" ); document.write( "PROBABILITY OF GETTING A GREEN MARBLE ON FIRST ATTEMPT=5/20=1/4
\n" ); document.write( "PROBABILITY OF GETTING A GREEN MARBLE ON SECOND ATTEMPT=
\n" ); document.write( "=PROBABILITY OF GETTING A GREEN MARBLE ON FIRST ATTEMPT AS THE MARBLE IS REPLACED =5/20=1/4
\n" ); document.write( "HENCE PROBABILITY OF DRAWING 2 GREEN MARBLES = (1/4)8(1/4)=1/16
\n" ); document.write( "HENCE PROBABILITY OF NOT DRAWING 2 GREEN MARBLES =1-1/16=15/16\r
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