document.write( "Question 194554: john had a square patio. after expanding the length by 20 ft and the wide by 10 ft the area was 999 ft^2 what was the perimeter of the original patio?
\n" ); document.write( "please help me to solve please...... help!!!!! \n" ); document.write( "
Algebra.Com's Answer #145993 by nerdybill(7384)\"\" \"About 
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john had a square patio. after expanding the length by 20 ft and the wide by 10 ft the area was 999 ft^2 what was the perimeter of the original patio?
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\n" ); document.write( "Let x = measure of one side of original square patio
\n" ); document.write( "then
\n" ); document.write( "x+20 = length of new
\n" ); document.write( "x+10 = width of new
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\n" ); document.write( "(x+20)(x+10) = 999
\n" ); document.write( "x^2+10x+20x+200 = 999
\n" ); document.write( "x^2+30x+200 = 999
\n" ); document.write( "x^2+30x-799 = 0
\n" ); document.write( "Factoring:
\n" ); document.write( "(x+47)(x-17) = 0
\n" ); document.write( "x = {-47, 17}
\n" ); document.write( "Tossing out the negative solution leaves:
\n" ); document.write( "x = 17 feet
\n" ); document.write( "Perimeter then is:
\n" ); document.write( "4*17 = 68 feet\r
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