document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=194543>Question 194543</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0153366095/algebrahomeworkh>Harcourt Math</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> For the given area, find the length and width of the rectangle with the least perimeter. Use whole numbers only.\r<BR>\n" );
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document.write( "30 m2<BR>\n" );
document.write( "40 yd2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145963 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For the given area, find the length and width of the rectangle with the least perimeter. Use whole numbers only. <BR>\n" );
document.write( "30 m2<BR>\n" );
document.write( "40 yd2<BR>\n" );
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document.write( "A square has the least perimeter for a rectangle. (A proof is available is needed.)<BR>\n" );
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document.write( "For squares, P = 4*s<BR>\n" );
document.write( "30 sq meters --> sides of sqrt(30) meters<BR>\n" );
document.write( "l = w = sqrt(30) = ~ 5.477 meters<BR>\n" );
document.write( "Using integers, --> 5 by 6.<BR>\n" );
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document.write( "40 sq yds --> sqrt(40)<BR>\n" );
document.write( "l = w = sqrt(40) = ~ 6.325 yards<BR>\n" );
document.write( "Using integers --> 5 by 8 yards<BR>\n" );
document.write( "This is a silly problem. </SPAN>\n" );
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