document.write( "Question 194519: Name the vertex and axis of symmetry for each quadratic function. Tell wherther the parabola opens up, down, left, or right.
\n" ); document.write( "x=2y^2+4y+5 \n" ); document.write( "

Algebra.Com's Answer #145948 by RAY100(1637) $\"\"$ $\"About$

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x = 2y^2 +4y +5
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\n" ); document.write( "Leading coefficient is positive therefore it opens to right
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\n" ); document.write( "y vertex is at -b/2a,,, -(4)/2(2) = (-1)
\n" ); document.write( "x vertex is found by substituting, x= 2(-1)^2 +4(-1) +5 = +3
\n" ); document.write( "Vertex is (3,-1)
\n" ); document.write( "axis of symmetry is y= -1
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\n" ); document.write( "checking by plotting a few points,,,(3,-1),,,(5,0),,,,(5,-2),,,,ok \n" ); document.write( "

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