document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=194512>Question 194512</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Name the vertex and axis of symmetry for each quadratic function.  Tell wherther the parabola opens up, down, left, or right.<BR>\n" );
document.write( "H(x)=-(x-6)^2+1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145945 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145945\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let  H(x) = y<BR>\n" );
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document.write( "y = (x-6)^2  +1<BR>\n" );
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document.write( "(y-1) = (x-6)^2,,,,,from  this  we  can  read,  vertex  at  (6,1),  <BR>\n" );
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document.write( "positive  leading  coefficient  means  it  is  pointing  up<BR>\n" );
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document.write( "Axis  of  symmetry  is   x=6<BR>\n" );
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document.write( "another  form  might  be,,, y=x^2 -12x +36 +1  =  x^2 -12x +37<BR>\n" );
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document.write( "vertex  of  x  is  -b/2a  =  -(-12)/2(1) =  +6,,, subst in  to  get  y= 1,,,,( 6,1)<BR>\n" );
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document.write( "check  by  plotting  a  few  points,  (6,1),,,,(5,2),,,,(7,2) </SPAN>\n" );
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