document.write( "Question 194397: The manager of a discount clothing store received two shipments of fall clothing. The cost of the first shipment which contained ten identical sweaters and twenty identical jackets was $800. The second shipment at the same prices, contained five of the same sweaters and fifteen of the same jackets. The second shipment was $550. Find the cost of one jacket. \n" ); document.write( "
Algebra.Com's Answer #145904 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 20J+10S=800 \n" ); document.write( "15J+5S=550 MULTIPLY THIS EQUATION BY -2 & ADD. \n" ); document.write( "-30J-10S=-1100 \n" ); document.write( "20J+10S=800 \n" ); document.write( "--------------------- \n" ); document.write( "-10J=-300 \n" ); document.write( "J=-300/-10 \n" ); document.write( "J=$30 THE PRICE OF EACH JACKET. \n" ); document.write( "20*3+10X=800 \n" ); document.write( "600+10X=800 \n" ); document.write( "10X=800-600 \n" ); document.write( "10X=200 \n" ); document.write( "X=200/10 \n" ); document.write( "X=$20 FOR EACH SWEATER. \n" ); document.write( "PROOF: \n" ); document.write( "15*30+5*20=550 \n" ); document.write( "450+100=550 \n" ); document.write( " \n" ); document.write( " |