document.write( "Question 194419: The manager of a discount store received two clothing shipments. The first shipment contained 10 sweaters and 20 jackets and cost $800. The second shipment, at the same prices, contained 5 sweaters and 15 jackets and costs $550. Find the cost of 1 jacket \n" ); document.write( "
Algebra.Com's Answer #145896 by checkley77(12844)\"\" \"About 
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20J+10S=800
\n" ); document.write( "15J+5S=550 MULTIPLY THIS EQUATION BY -2 & ADD.
\n" ); document.write( "-30J-10S=-1100
\n" ); document.write( "20J+10S=800
\n" ); document.write( "---------------------
\n" ); document.write( "-10J=-300
\n" ); document.write( "J=-300/-10
\n" ); document.write( "J=$30 THE PRICE OF EACH JACKET.
\n" ); document.write( "20*3+10X=800
\n" ); document.write( "600+10X=800
\n" ); document.write( "10X=800-600
\n" ); document.write( "10X=200
\n" ); document.write( "X=200/10
\n" ); document.write( "X=$20 FOR EACH SWEATER.
\n" ); document.write( "PROOF:
\n" ); document.write( "15*30+5*20=550
\n" ); document.write( "450+100=550
\n" ); document.write( "550=550
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