document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=194427>Question 194427</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Extraneous Solution<BR>\n" );
document.write( "Question: 5/y-3 = y+7/2y -6 + 1  LCD is 2(y-3)?<BR>\n" );
document.write( "          2(y-3)* 5/y-3= y+7/2y-6*2(y-3 + 1 * 2(y-3)<BR>\n" );
document.write( "          I'm stuck. I don't think I have the correct LCD.<BR>\n" );
document.write( "          where did I go wrong? Thank You for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145883 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145883\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Question: 5/(y-3) = (y+7)/(2y-6) + 1 LCM is 2(y-3)?\r<BR>\n" );
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document.write( "--------------<BR>\n" );
document.write( "Multiply thru by the LCM to get:<BR>\n" );
document.write( "5(2) = (y+7) + 2(y-3)<BR>\n" );
document.write( "10 = 3y +1<BR>\n" );
document.write( "y = 3<BR>\n" );
document.write( "===========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );