document.write( "Question 194404: A norman window is one that consists of a rectangle with a curved top to it. the curved top is actually a semicircle that sits on top of the rectangle. if the perimeter around the norman window is 20 feet, what radius of the semicircle will provide the greatest window area? \n" ); document.write( "
Algebra.Com's Answer #145874 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A norman window is one that consists of a rectangle with a curved top to it. \n" ); document.write( "the curved top is actually a semicircle that sits on top of the rectangle. \n" ); document.write( " if the perimeter around the norman window is 20 feet, what radius of the \n" ); document.write( " semicircle will provide the greatest window area? \n" ); document.write( ": \n" ); document.write( "Let H = the height of the rectangular portion of the window \n" ); document.write( ": \n" ); document.write( "Let x = the radius of the semi circle on top \n" ); document.write( ": \n" ); document.write( "Half the circumference = pi*x \n" ); document.write( ": \n" ); document.write( "Width of the window = 2x \n" ); document.write( ": \n" ); document.write( "The perimeter: \n" ); document.write( "2H + 2x + pix = 20 \n" ); document.write( "Solve for H \n" ); document.write( "2H = 20 - 2x - pix \n" ); document.write( "H = \n" ); document.write( ": \n" ); document.write( "Area formula: A = (H*2x) + .5pi*x^2 \n" ); document.write( "Replace H with \n" ); document.write( "A = 2x( \n" ); document.write( "Cancel the 2 \n" ); document.write( "A = \n" ); document.write( "A = \n" ); document.write( "Leaving us with \n" ); document.write( "A = \n" ); document.write( ".5*pi = 1.57 \n" ); document.write( "A = \n" ); document.write( "A = \n" ); document.write( "A quadratic equation, find the vertex for max area; a=-3.57, b=20 \n" ); document.write( "x = \n" ); document.write( "x = \n" ); document.write( "x = 2.8 ft radius for max area \n" ); document.write( ": \n" ); document.write( "Check solution by finding the perimeter with this radius \n" ); document.write( "Find 2H \n" ); document.write( "2H = 20 - 2(2.8) - 2.8pi \n" ); document.write( "2H = 5.6 ft \n" ); document.write( "Find perimeter: \n" ); document.write( "2H + 2x + pix = 20 \n" ); document.write( "5.6 + 2(2.8) + 2.8*pi = \n" ); document.write( "5.6 + 5.6 + 8.8 = 20 \n" ); document.write( "; \n" ); document.write( "note that max area is when the rectangular portion, is a square, 5.6 by 5.6\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |