document.write( "Question 194333: a right triangle has one vertex on the graph of y = x^2 at (x,y),another at the origin, and the third on the positive y- axis at (0,y). express the area A of the triangle as a function of x. for what value of x will be the area of the triangle be equal to 30 square units?\r
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Algebra.Com's Answer #145842 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First, let's draw a picture:\r
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\n" ); document.write( "\n" ); document.write( "Now since the point (x,y) is \"x\" units to the right and \"y\" units up, this means that the base of the triangle is \"x\" units long and the height is \"y\" units high. Now let's label the drawing:\r
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\n" ); document.write( "\n" ); document.write( "But remember, we let \"y=x%5E2\". So replace \"y\" with \"x%5E2\" to get\r
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\n" ); document.write( "\n" ); document.write( "Now focusing on just the triangle, we get the following\r
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\n" ); document.write( "\n" ); document.write( "So the base is \"x\" and the height is \"x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Now recall (or look up), the area of any triangle is \"A=%28bh%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=%28bh%29%2F2\" Start with the given formula \r
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\n" ); document.write( "\n" ); document.write( "\"A=%28x%2Ax%5E2%29%2F2\" Plug in \"b=x\" and \"h=x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=x%5E3%2F2\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So the area is \"A=x%5E3%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"for what value of x will be the area of the triangle be equal to 30 square units?\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=x%5E3%2F2\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"30=x%5E3%2F2\" Plug in \"A=30\"\r
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\n" ); document.write( "\n" ); document.write( "\"30%2A2=x%5E3\" Multiply both sides by 2.\r
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\n" ); document.write( "\n" ); document.write( "\"60=x%5E3\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3=60\" Rearrange the equation\r
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\n" ); document.write( "\n" ); document.write( "\"x=root%283%2C60%29\" Take the cube root of both sides.\r
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\n" ); document.write( "\n" ); document.write( " Approximate the right side with a calculator.\r
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\n" ); document.write( "\n" ); document.write( "So the answer is approximately
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