document.write( "Question 194280: Solve the equation for x.
\n" ); document.write( "125^x-2=25^3x+1 \n" ); document.write( "

Algebra.Com's Answer #145827 by Earlsdon(6294) $\"\"$ $\"About$

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Solve for x:
\n" ); document.write( " $\"125%5E%28%28x-2%29%29+=+25%5E%28%283x%2B1%29%29\"$ Substitute $\"125+=+5%5E3\"$ and $\"25+=5%5E2\"$
\n" ); document.write( " $\"%285%5E%283%29%29%5E%28%28x-2%29%29+=+%285%5E2%29%5E%28%283x%2B1%29%29\"$ Simplify.
\n" ); document.write( " $\"5%5E%28%283x-6%29%29+=+5%5E%28%286x%2B2%29%29\"$ The bases (5) are equal so the exponents are equal.
\n" ); document.write( " $\"3x-6+=+6x%2B2\"$ Subtract 3x from both sides.
\n" ); document.write( " $\"-6+=+3x%2B2\"$ Subtract 2 from both sides.
\n" ); document.write( " $\"-8+=+3x\"$ Divide both sides by 3.
\n" ); document.write( " $\"x+=+-8%2F3\"$
\n" ); document.write( "Solution:
\n" ); document.write( "x = -2 2/3 \n" ); document.write( "

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