document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=194294>Question 194294</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1602773033/algebrahomeworkh>saxon algebra 2</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> What is the solution of (x+3)/(x-5)(x-2)>0? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145804 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145804\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+3)/(x-5)(x-2)>0<BR>\n" );
document.write( "x cannot be 5 or 2 because there would be division by zero. Therefore 2 and 5 are inflection points and we have to test whether the inequality is >0 on either side of them.<BR>\n" );
document.write( "Let x=1: (1+3)/(1-5)(1-2)=1<BR>\n" );
document.write( "Let x=3: (3+3)/(3-5)(3-2)=-3<BR>\n" );
document.write( "Let x=6: (6+3)/(6-3)(6-2)=3/4<BR>\n" );
document.write( "So x(-infinity,2)U(5, infinity) Answer.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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