document.write( "Question 194293This question is from textbook saxon algebra 2
\n" ); document.write( ": If 6 square root 6x-1-18(-18 is not under square root sign)=0, then x=
\n" ); document.write( "5/6. Did I calculate this correctly?
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Algebra.Com's Answer #145801 by nerdybill(7384)\"\" \"About 
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\n" ); document.write( "\"6sqrt%286x-1%29+-+18+=+0\"
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\n" ); document.write( "\"6sqrt%286x-1%29+=+18\"
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\n" ); document.write( "\"sqrt%286x-1%29+=+3\"
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\n" ); document.write( "\"6x-1+=+9\"
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\n" ); document.write( "\"6x+=+10\"
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\n" ); document.write( "\"x+=+10%2F6\"
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\n" ); document.write( "\"x+=+5%2F3\"
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