document.write( "Question 194288This question is from textbook Survey of Mathematics w/Apps
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document.write( ": I tried using the solver but it did not make any sense. Please help me with this question. This is a two part question, A) Find the supplementary angle of 34 dgrees which is 146 degrees which I have, but Part \"B\" I don't quite understand is below:
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document.write( "Angle ABC and angle PQR are supplementary angles and angle ABC is eleven time as large as angle PQR. Determine the measure of each angle. \n" );
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Algebra.Com's Answer #145796 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Let a=angle ABC and p=angle PQR \n" ); document.write( "a=11p \n" ); document.write( "180-p=a \n" ); document.write( "180-p=11p substitute 11p for a. \n" ); document.write( "12p=180 \n" ); document.write( "p=15 \n" ); document.write( "a=165 \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |