document.write( "Question 194257: Solve:\r
\n" ); document.write( "\n" ); document.write( "log(6)(x+7)-log(6)(x-2)=log(6)5
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Algebra.Com's Answer #145789 by nerdybill(7384)\"\" \"About 
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Apply \"log rules\":
\n" ); document.write( "log(6)(x+7)-log(6)(x-2)=log(6)5
\n" ); document.write( "log(6)((x+7)/(x-2))=log(6)5
\n" ); document.write( "(x+7)/(x-2) = 5
\n" ); document.write( "(x+7) = 5(x-2)
\n" ); document.write( "x+7 = 5x-10
\n" ); document.write( "7 = 4x-10
\n" ); document.write( "17 = 4x
\n" ); document.write( "17/4 = x\r
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