document.write( "Question 194218: Can you help me please? Solve the system by the addition method. \r
\n" ); document.write( "\n" ); document.write( "x – y = 100
\n" ); document.write( "0.20x + 0.06y = 150\r
\n" ); document.write( "\n" ); document.write( "Thank you all \n" ); document.write( "

Algebra.Com's Answer #145765 by nerdybill(7384) $\"\"$ $\"About$

You can put this solution on YOUR website!
Starting with:
\n" ); document.write( "x – y = 100
\n" ); document.write( "0.20x + 0.06y = 150
\n" ); document.write( ".
\n" ); document.write( "Multiply both sides of the top equation by 0.06:
\n" ); document.write( "0.06x – 0.06y = 6
\n" ); document.write( "0.20x + 0.06y = 150
\n" ); document.write( ".
\n" ); document.write( "Now, add both top and bottom equation together:
\n" ); document.write( "0.06x – 0.06y = 6
\n" ); document.write( "0.20x + 0.06y = 150
\n" ); document.write( "----------------------
\n" ); document.write( "0.26x = 156
\n" ); document.write( "x = 156/0.26
\n" ); document.write( "x = 600
\n" ); document.write( ".
\n" ); document.write( "Substitute the above back into the first equation:
\n" ); document.write( "x – y = 100
\n" ); document.write( "600 – y = 100
\n" ); document.write( "-y = 400
\n" ); document.write( "y = -400
\n" ); document.write( ".
\n" ); document.write( "(x,y) = (600, -400) \n" ); document.write( "

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