document.write( "Question 194212: log x = log6 36 + log81 9 – log2 4\r
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Algebra.Com's Answer #145763 by nerdybill(7384)\"\" \"About 
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log x = log6 36 + log81 9 – log2 4
\n" ); document.write( "we can rewrite as:
\n" ); document.write( "log x = log6 6^2 + log81 81^(1/2) – log2 2^2
\n" ); document.write( "Now we simplify:
\n" ); document.write( "log x = 2 + (1/2) – 2
\n" ); document.write( "log x = 1/2
\n" ); document.write( "x = 10^(1/2)
\n" ); document.write( "x = 3.162
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