document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=194189>Question 194189</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780741913647/algebrahomeworkh>academic systems elementary algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Hi, here is a problem I've been stuck on, please help, if possible!\r<BR>\n" );
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document.write( "In 7 years, Maria will be 4 times as old as Angelica will be then. The sum of their ages is now 71. How old will each of them be in 5 years?\r<BR>\n" );
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document.write( "So far, I've got a chart like this:\r<BR>\n" );
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document.write( "Maria: In 7 years: 4(x+7).  In 5 Years: x+5 (not sure if Maria is still 4 times older than Angelica in 5 years?)\r<BR>\n" );
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document.write( "Angelica:  In 7 years: x+7.  In 5 Years: x+5.     =71\r<BR>\n" );
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document.write( "I put the equation together like this:\r<BR>\n" );
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document.write( "4(x+7) - (x+5)= 71\r<BR>\n" );
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document.write( "4(x + 28) - (x+5)= 71\r<BR>\n" );
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document.write( "4x + 28 - (x+5) = 71\r<BR>\n" );
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document.write( "4x - x +28 - 5 = 71\r<BR>\n" );
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document.write( "3x + 23 = 71\r<BR>\n" );
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document.write( "3x =48\r<BR>\n" );
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document.write( "X = 16\r<BR>\n" );
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document.write( "The solution I get is 16, but the answer at the back of the book says Angelica is 15, and Maria is 66! What did I do wrong, and what is the correct way to solve? Any help would be great, thanks!\r<BR>\n" );
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document.write( "Leanne Rain </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145756 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145756\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In 7 years, Maria will be 4 times as old as Angelica will be then. The sum of their ages is now 71. How old will each of them be in 5 years? <BR>\n" );
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document.write( "NOW DATA:<BR>\n" );
document.write( "Let Maria be \"M\" yrs. old<BR>\n" );
document.write( "Then Angel is \"71-M\"<BR>\n" );
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document.write( "7 yrs from NOW DATA:<BR>\n" );
document.write( "Maria will be \"M+7\"<BR>\n" );
document.write( "Angel will be \"71-M+7\" = 78-M<BR>\n" );
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document.write( "Equation based on 7 yrs. from NOW DATA:<BR>\n" );
document.write( "M+7 = 4(78-M)<BR>\n" );
document.write( "M+7 = 312 - 4M<BR>\n" );
document.write( "5M = 305<BR>\n" );
document.write( "M = 61 (Maria's age NOW)<BR>\n" );
document.write( "Angel = 71-M = 71-61 = 10 (Angel's age NOW)<BR>\n" );
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document.write( "5 yrs from NOW<BR>\n" );
document.write( "Maria will be 61+5 = 65<BR>\n" );
document.write( "Angel will be 10+5 = 15<BR>\n" );
document.write( "=============================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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