document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=194162>Question 194162</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395977258/algebrahomeworkh>Find Algebra and Trigonometry: Structure and Method (2nd) </A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> 1. Find the demensions of a rectangle whose perimeter is 50m and whose area is 144 m2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145755 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LW=144 OR L=144/W<BR>\n" );
document.write( "2L+2W=50<BR>\n" );
document.write( "2(144/W)+2W=50<BR>\n" );
document.write( "288/W+2W=50<BR>\n" );
document.write( "(288+2W*W)/W=50<BR>\n" );
document.write( "(288+2W^2)/W=50<BR>\n" );
document.write( "2W^2+288=50W<BR>\n" );
document.write( "2W^2-50W+288=0<BR>\n" );
document.write( "2(W^2-25W+144)=0<BR>\n" );
document.write( "2(W-16)(W-9)=0<BR>\n" );
document.write( "W-16=0<BR>\n" );
document.write( "W=16 ANS. L=9 ANS<BR>\n" );
document.write( "W-9=0<BR>\n" );
document.write( "W=9 ANS. L=16 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*16+2*9=50<BR>\n" );
document.write( "32+18=50<BR>\n" );
document.write( "50=50\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );