document.write( "Question 193874: let log2=0.03+log3=0.05 find
\n" ); document.write( "log(3/2) \n" ); document.write( "

Algebra.Com's Answer #145723 by nerdybill(7384) $\"\"$ $\"About$

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Applying log rules:
\n" ); document.write( "let log2=0.03+log3=0.05 find
\n" ); document.write( "log(3/2)
\n" ); document.write( ".
\n" ); document.write( "log(3/2)
\n" ); document.write( "can be rewritten as:
\n" ); document.write( "log(3) - log(2)
\n" ); document.write( "then, replace with given values:
\n" ); document.write( "0.05 - 0.03 = 0.02 \n" ); document.write( "

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