document.write( "Question 194062: How do you find the square root of 75x3y5? \n" ); document.write( "
Algebra.Com's Answer #145656 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"sqrt%2875%2Ax%5E3%2Ay%5E5%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%2825%2A3%2Ax%5E3%2Ay%5E5%29\" Factor \"75\" into \"25%2A3\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%2825%2A3%2Ax%5E2%2Ax%2Ay%5E5%29\" Factor \"x%5E3\" into \"x%5E2%2Ax\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%2825%2A3%2Ax%5E2%2Ax%2Ay%5E2%2Ay%5E2%2Ay%29\" Factor \"y%5E5\" into \"y%5E2%2Ay%5E2%2Ay\"\r
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\n" ); document.write( "\n" ); document.write( " Break up the square root using the identity \"sqrt%28A%2AB%29=sqrt%28A%29%2Asqrt%28B%29\".\r
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\n" ); document.write( "\n" ); document.write( " Take the square root of \"25\" to get \"5\".\r
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\n" ); document.write( "\n" ); document.write( "\"5%2Asqrt%283%29%2Ax%2Asqrt%28x%29%2Asqrt%28y%5E2%29%2Asqrt%28y%5E2%29%2Asqrt%28y%29\" Take the square root of \"x%5E2\" to get \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"5%2Asqrt%283%29%2Ax%2Asqrt%28x%29%2Ay%2Ay%2Asqrt%28y%29\" Take the square root of \"y%5E2\" to get \"y\".\r
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\n" ); document.write( "\n" ); document.write( "\"5xy%5E2%2Asqrt%283xy%29\" Rearrange and combine the terms.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"sqrt%2875%2Ax%5E3%2Ay%5E5%29\" simplifies to \"5xy%5E2%2Asqrt%283xy%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"sqrt%2875%2Ax%5E3%2Ay%5E5%29=5xy%5E2%2Asqrt%283xy%29\" where every variable is non-negative.
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