document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=194019>Question 194019</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You invest money into an account where the interest is compounded continuously. If the accounts value doubles in 9 years, what is the interest rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145646 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145646\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> continuous  interest  formula  is  A=Pe^rt,  <BR>\n" );
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document.write( "A=Pe^rt<BR>\n" );
document.write( "A/P= 2 = e^(r*9)<BR>\n" );
document.write( "ln  both  sides<BR>\n" );
document.write( "ln2 = 9r,,,,,,,,,,,,,,,,,,,,,,,,ln e^rt = rt<BR>\n" );
document.write( "lnr/9 = .077 = r<BR>\n" );
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document.write( "check<BR>\n" );
document.write( "A=Pe^rt<BR>\n" );
document.write( "A/P = 2 = e^(.077 * 9) =2,,,,,ok </SPAN>\n" );
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