document.write( "Question 26777: i dont get how to set the problem up. once i get the problem set up, i can do it. please help?\r
\n" ); document.write( "\n" ); document.write( "Your chemistry teacher asks you to mix 20% acid solution with 50% acid solution to obtain 12 ounces of 30% acid solution. how much of each must you use?
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Algebra.Com's Answer #14563 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
20x+50(12-x)=30(12)
\n" ); document.write( "20x+600-50x=360
\n" ); document.write( "-30x=-240
\n" ); document.write( "x=8\r
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\n" ); document.write( "\n" ); document.write( "12-8=4\r
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\n" ); document.write( "\n" ); document.write( "Hence, for 20% there should be 8 ounces added and for 50% there should be 4 ounces added.
\n" ); document.write( "Paul.
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