document.write( "Question 193977: Ms. Burke invested $15,000 in two accounts, one yielding 5% interest and the other 12%. If she received a total of $1,380 in interest at the end of the year, how much in each account? \n" ); document.write( "
Algebra.Com's Answer #145622 by checkley77(12844)\"\" \"About 
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.12X+.05(15,000-X)=1,380
\n" ); document.write( ".12X+750-.05X=1,380
\n" ); document.write( ".07X=1,380-750
\n" ); document.write( ".07X=630
\n" ); document.write( "X=630/.07
\n" ); document.write( "X=$9,000 IS THE AMOUNT INVESTED @ 12%.
\n" ); document.write( "15,000-9,000=6,000 IS THE AMOUNT INVESTED @ 5%
\n" ); document.write( "pROOF:
\n" ); document.write( ".12*9,000+.05*6,000=1,380
\n" ); document.write( "1,080+300=1,380
\n" ); document.write( "1,380=1,380
\n" ); document.write( "
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