document.write( "Question 26767: the excursion boat Holiday travels 35km upstream and then back again in 4h 48 min. If the speed of the Holiday in still water is 15 km/h, what is the speed of the current? \n" ); document.write( "

Algebra.Com's Answer #14561 by Paul(988) $\"\"$ $\"About$

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4 h and 48 minutes = 4.8hours
\n" ); document.write( " $\"35%2F%28x%2B15%29%2B35%2F%2815-x%29=4.8\"$
\n" ); document.write( "35[(x+15)+(15-x)=4.8[{x+15)(15-x)]
\n" ); document.write( " $\"35%2830%29=4.8%28-x%5E2%2B225%29\"$
\n" ); document.write( " $\"1050=-4.8x%5E2%2B1080\"$
\n" ); document.write( " $\"4.8x%5E2=30\"$
\n" ); document.write( " $\"x%5E2=6.25\"$
\n" ); document.write( "x=2.5\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hence, the speed of the current is 2.5km/h.
\n" ); document.write( "Paul. \n" ); document.write( "

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