document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=193964>Question 193964</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm not sure if this goes here, but anything without set equations is a word problem to me. Can someone help me?<BR>\n" );
document.write( "The width of a rectangle is fixed at 25cm. What lengths will make the perimeter greater than 90cm?<BR>\n" );
document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145587 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145587\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> formula  for perimeter  is  Perimeter = 2Length + 2Width<BR>\n" );
document.write( ",<BR>\n" );
document.write( "P = 2l +2(25) = 2l +50<BR>\n" );
document.write( "but  perimeter >90<BR>\n" );
document.write( "2l +50  > 90<BR>\n" );
document.write( "2l > 40<BR>\n" );
document.write( "l>20 ,,,,,,,, ANSWER<BR>\n" );
document.write( ",<BR>\n" );
document.write( "check<BR>\n" );
document.write( "l>20=21,  P=2l +2w = 2(21) +2 (25) = 92,  ok   </SPAN>\n" );
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