document.write( "Question 193910: Sandy bicycled 45 miles going east from Cambridge and Janie, 70 miles. Janie averaged 5 miles per hour more than Sandy and her trip took 1/2 hour longer than Sandy's. How fast was each one traveling? \n" ); document.write( "
Algebra.Com's Answer #145586 by ankor@dixie-net.com(22740)\"\" \"About 
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Sandy bicycled 45 miles going east from Cambridge and Janie, 70 miles. Janie averaged 5 miles per hour more than Sandy and her trip took 1/2 hour longer than Sandy's. How fast was each one traveling?
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\n" ); document.write( "I assume this means that Sandy traveled 45 miles and Janie traveled 70 miles.
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\n" ); document.write( "let s = Sandy's speed
\n" ); document.write( "then
\n" ); document.write( "(s+5) = Janie's speed
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\n" ); document.write( "Write a time equation; time = dist/speed
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\n" ); document.write( "Janie's travel time = Sandy's travel time + .5 hrs
\n" ); document.write( "\"70%2F%28%28s%2B5%29%29\" = \"45%2Fs\" + .5
\n" ); document.write( "Multiply equation by s(s+5) to get rid of the denominators, results:
\n" ); document.write( "70s = 45(s+5) + .5s(s+5)
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\n" ); document.write( "70s = 45s + 225 + .5s^2 + 2.5s
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\n" ); document.write( "0 = .5s^2 + 2.5s + 45s - 70s + 225
\n" ); document.write( "A quadratic equation
\n" ); document.write( ".5s^2 - 22.5s + 225 = 0
\n" ); document.write( "Multiply equation by 2 to eliminate the decimals
\n" ); document.write( "s^2 - 45s + 450 = 0
\n" ); document.write( "Factor
\n" ); document.write( "(s - 15)(s - 30) = 0
\n" ); document.write( "Two solutions for Sandy's speed
\n" ); document.write( "s = 15
\n" ); document.write( "and
\n" ); document.write( "s = 30
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\n" ); document.write( "Check using both solutions by finding the times;
\n" ); document.write( "Sandy: 15 mph; Janie: 20 mph
\n" ); document.write( "70/20 = 3.5 hr
\n" ); document.write( "45/15 = 3.0 hr; a half hr difference
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\n" ); document.write( "Sandy: 30 mph; Janie: 35 mph
\n" ); document.write( "70/35 = 2 hrs
\n" ); document.write( "45/30 = 1.5 hrs; a half hr difference here too
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