document.write( "Question 193885: the second term of the infinite geometric series, \r
\n" ); document.write( "\n" ); document.write( "a + ar + ar^2 + ar^3......\r
\n" ); document.write( "\n" ); document.write( "is eaqual to 4 and the same to infinity of this series is 18. Find the two possible values of the common ratio, r. what are the corresponding values of a?
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Algebra.Com's Answer #145564 by stanbon(75887)\"\" \"About 
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the second term of the infinite geometric series,
\n" ); document.write( "a + ar + ar^2 + ar^3......
\n" ); document.write( "is equal to 4 and the same to infinity of this series is 18. Find the two possible values of the common ratio, r. what are the corresponding values of a?
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\n" ); document.write( "2nd term: a(2) = ar = 4
\n" ); document.write( "Sum : a/(1-r) = 18
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\n" ); document.write( " Rearrange:
\n" ); document.write( "a = 4/r
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\n" ); document.write( "Substitute:
\n" ); document.write( "(4/r)/(1-r) = 18
\n" ); document.write( "4/r = 18 - 18r
\n" ); document.write( "4 = 18r-18r^2
\n" ); document.write( "18r^2 - 18r +4 = 0
\n" ); document.write( "9r^2 - 9r + 2 = 0
\n" ); document.write( "9r^2 - 6r - 3r + 2 = 0
\n" ); document.write( "3r(3r-2)-(3r-2) = 0
\n" ); document.write( "(3r-2)(3r-1) = 0
\n" ); document.write( "r = 2/3 or r = 1/3
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\n" ); document.write( "Since a = 4/r
\n" ); document.write( "a = 6 when r = 2/3 or a = 12 when r = 1/3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H
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