document.write( "Question 193878: \n" ); document.write( "
Algebra.Com's Answer #145558 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
# 1\r
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\n" ); document.write( "\n" ); document.write( "Let \r
\n" ); document.write( "\n" ); document.write( "x = measure of < PQR and \r
\n" ); document.write( "\n" ); document.write( "y = measure of < ABC\r
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\n" ); document.write( "\n" ); document.write( "Since these two angles are complementary angles, this means that the two angles add to 90 degrees. So \"x%2By=90\". Let's label this equation 1.\r
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\n" ); document.write( "\n" ); document.write( "Also, because \"< PQR is nine times as large as < ABC\", we know that \"x=9y\". We'll call this equation 2.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2By=90\" Start with the first equation\r
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\n" ); document.write( "\n" ); document.write( "\"9y%2By=90\" Plug in \"x=9y\"\r
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\n" ); document.write( "\n" ); document.write( "\"10y=90\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%2890%29%2F%2810%29\" Divide both sides by \"10\" to isolate \"y\".\r
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\n" ); document.write( "\n" ); document.write( "\"y=9\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"x=9y\" Go back to the second equation\r
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\n" ); document.write( "\n" ); document.write( "\"x=9%289%29\" Plug in \"y=9\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=81\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=81\" and \"y=9\" which means that the measures of < PQR and < ABC are 81 and 9 degrees respectively.\r
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\n" ); document.write( "\n" ); document.write( "# 2\r
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\n" ); document.write( "\n" ); document.write( "Take note that the angle marked 68 degrees and angle 3 are vertical angles. So this means that these two angles are equal.\r
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\n" ); document.write( "\n" ); document.write( "So angle 3 is also 68 degrees.\r
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\n" ); document.write( "\n" ); document.write( "Now because lines l and m are parallel, this means that the alternate interior angles are equal. Since angles 3 and 5 are alternate interior angles, this tells us that\r
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\n" ); document.write( "\n" ); document.write( "angle 3 = angle 5\r
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\n" ); document.write( "\n" ); document.write( "So angle 5 is 68 degrees as well.\r
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\n" ); document.write( "\n" ); document.write( "Now remember, the sum of the 3 angles of ANY triangle is ALWAYS 180 degrees. So if we let the measure of angle 6 be \"x\", this means that\r
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\n" ); document.write( "\n" ); document.write( "40 + angle 5 + angle 6 = 180\r
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\n" ); document.write( "\n" ); document.write( "Plug in the given values to get:\r
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\n" ); document.write( "\n" ); document.write( "40 + 68 + x = 180\r
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\n" ); document.write( "\n" ); document.write( "Combine like terms to get \r
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\n" ); document.write( "\n" ); document.write( "108 + x = 180\r
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\n" ); document.write( "\n" ); document.write( "Subtract 108 from both sides \r
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\n" ); document.write( "\n" ); document.write( "x = 180 - 108\r
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\n" ); document.write( "\n" ); document.write( "and combine like terms to get\r
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\n" ); document.write( "\n" ); document.write( "x = 72\r
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\n" ); document.write( "\n" ); document.write( "So the measure of angle 6 is 72 degrees.\r
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\n" ); document.write( "\n" ); document.write( "# 3\r
\n" ); document.write( "\n" ); document.write( "a)\r
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\n" ); document.write( "\n" ); document.write( "First, let \"x\" be the length of AC to get the triangle:\r
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\n" ); document.write( "\n" ); document.write( "To find the unknown length, we need to use the Pythagorean Theorem.\r
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\n" ); document.write( "\n" ); document.write( "Remember, the Pythagorean Theorem is \"a%5E2%2Bb%5E2=c%5E2\" where \"a\" and \"b\" are the legs of a triangle and \"c\" is the hypotenuse.\r
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\n" ); document.write( "\n" ); document.write( "Since the legs are \"x\" and \"12\" this means that \"a=x\" and \"b=12\"\r
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\n" ); document.write( "\n" ); document.write( "Also, since the hypotenuse is \"13\", this means that \"c=13\".\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2%2Bb%5E2=c%5E2\" Start with the Pythagorean theorem.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B12%5E2=13%5E2\" Plug in \"a=x\", \"b=12\", \"c=13\" \r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B144=13%5E2\" Square \"12\" to get \"144\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B144=169\" Square \"13\" to get \"169\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=169-144\" Subtract \"144\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=25\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%2825%29\" Take the square root of both sides. Note: only the positive square root is considered (since a negative length doesn't make sense).\r
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\n" ); document.write( "\n" ); document.write( "\"x=5\" Take the square root of 25 to get 5.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=5\" which means that AC = 5.\r
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\n" ); document.write( "\n" ); document.write( "b)\r
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\n" ); document.write( "\n" ); document.write( "Now that we know the three sides are of length 5, 12, and 13 units, simply add them up to get\r
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\n" ); document.write( "\n" ); document.write( "Perimeter = 5 + 12 + 13 = 17 + 13 = 30\r
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\n" ); document.write( "\n" ); document.write( "So the perimeter is 30 units.\r
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\n" ); document.write( "\n" ); document.write( "c)\r
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\n" ); document.write( "\n" ); document.write( "Recall, the area of a triangle is \"A=%28bh%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=%28bh%29%2F2\" Start with the given formula.\r
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\n" ); document.write( "\n" ); document.write( "\"A=%2812%2A5%29%2F2\" Plug in the given base and height.\r
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\n" ); document.write( "\n" ); document.write( "\"A=60%2F2\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"A=30\" Divide.\r
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\n" ); document.write( "\n" ); document.write( "So the area is 30 square units.\r
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\n" ); document.write( "\n" ); document.write( "Note: this is just a coincidence that the perimeter and the area are equal.\r
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\n" ); document.write( "\n" ); document.write( "# 4\r
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\n" ); document.write( "\n" ); document.write( "First, we need to find the length of diagonal.\r
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\n" ); document.write( "\n" ); document.write( "If we cut the garden in half along the diagonal, we'll have this triangle set up (where \"x\" is the length of the diagonal):\r
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\n" ); document.write( "\n" ); document.write( "Remember, the Pythagorean Theorem is \"a%5E2%2Bb%5E2=c%5E2\" where \"a\" and \"b\" are the legs of a triangle and \"c\" is the hypotenuse.\r
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\n" ); document.write( "\n" ); document.write( "Since the legs are \"18\" and \"24\" this means that \"a=18\" and \"b=24\"\r
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\n" ); document.write( "\n" ); document.write( "Also, since the hypotenuse is \"x\", this means that \"c=x\".\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2%2Bb%5E2=c%5E2\" Start with the Pythagorean theorem.\r
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\n" ); document.write( "\n" ); document.write( "\"18%5E2%2B24%5E2=x%5E2\" Plug in \"a=18\", \"b=24\", \"c=x\" \r
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\n" ); document.write( "\n" ); document.write( "\"324%2B24%5E2=x%5E2\" Square \"18\" to get \"324\".\r
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\n" ); document.write( "\n" ); document.write( "\"324%2B576=x%5E2\" Square \"24\" to get \"576\".\r
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\n" ); document.write( "\n" ); document.write( "\"900=x%5E2\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=900\" Rearrange the equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%28900%29\" Take the square root of both sides. Note: only the positive square root is considered (since a negative length doesn't make sense).\r
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\n" ); document.write( "\n" ); document.write( "\"x=30\" Take the square root of 900 to get 30.\r
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\n" ); document.write( "\n" ); document.write( "So the diagonal is 30 meters long. \r
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\n" ); document.write( "\n" ); document.write( "Now just multiply the length of the diagonal by the cost per linear meter to get: \r
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\n" ); document.write( "\n" ); document.write( "\"30%2A12=360\"\r
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\n" ); document.write( "\n" ); document.write( "So it will cost $360 to build the diagonal walkway.\r
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\n" ); document.write( "\n" ); document.write( "# 5\r
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\n" ); document.write( "\n" ); document.write( "First, let's convert every given measurement to feet. Recall (or look up), the given equality: \r
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\n" ); document.write( "\n" ); document.write( "1 yard = 3 feet\r
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\n" ); document.write( "\n" ); document.write( "In other words, there are 3 feet in a yard\r
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\n" ); document.write( "\n" ); document.write( "So to convert 16 yards to feet, simply multiply both sides of the equation given above by 16 to get\r
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\n" ); document.write( "\n" ); document.write( "1*16 yards = 3*16 feet\r
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\n" ); document.write( "\n" ); document.write( "16 yards = 48 feet\r
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\n" ); document.write( "\n" ); document.write( "So there are 48 feet in 16 yards\r
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\n" ); document.write( "\n" ); document.write( "Now go back to the original equation, but now multiply both sides by 70 to get:\r
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\n" ); document.write( "\n" ); document.write( "1*70 yards = 3 * 70 feet\r
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\n" ); document.write( "\n" ); document.write( "70 yards = 210 feet\r
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\n" ); document.write( "\n" ); document.write( "So there are 210 feet in 70 yards\r
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\n" ); document.write( "\n" ); document.write( "Note: to convert yards to feet, all we're doing is multiplying the given measurement in yards by 3\r
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\n" ); document.write( "\n" ); document.write( "So the equivalent dimensions (in feet) are 48 feet by 210 feet\r
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\n" ); document.write( "\n" ); document.write( "Now let's find the area of the lawn:\r
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\n" ); document.write( "\n" ); document.write( "The formula for the area of a rectangle is:\r
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\n" ); document.write( "\n" ); document.write( " Area = Length * Width \r
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\n" ); document.write( "\n" ); document.write( "which looks like: \"A=LW\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=LW\" Start with the given formula\r
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\n" ); document.write( "\n" ); document.write( "\"A=48%2A210\" Plug in the given dimensions (in feet)\r
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\n" ); document.write( "\n" ); document.write( "\"A=10800\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So the area of the lawn is 10,800 square feet.\r
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\n" ); document.write( "\n" ); document.write( "Now divide the area of the lawn by the area that ONE bag can cover to get:\r
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\n" ); document.write( "\n" ); document.write( "\"10800%2F525=20.571\"\r
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\n" ); document.write( "\n" ); document.write( "So it will take 21 bags to cover his lawn (I rounded to the nearest whole number since you can't buy half a bag)\r
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\n" ); document.write( "\n" ); document.write( "Now multiply this figure by the cost per bag to get: \"21%2A5.75=120.75\"\r
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\n" ); document.write( "\n" ); document.write( "So it will cost him $120.75 to cover his lawn with fertilizer.\r
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\n" ); document.write( "\n" ); document.write( "# 6\r
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\n" ); document.write( "\n" ); document.write( "Note: since the diameter is 22mm, we take half of this number to find the radius. So the radius is 11 mm (since 11 is half of 22)\r
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\n" ); document.write( "\n" ); document.write( "Area:\r
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\n" ); document.write( "\n" ); document.write( "Recall, the area of a circle is \"A=pi%2Ar%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=pi%2Ar%5E2\" Start with the given formula.\r
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\n" ); document.write( "\n" ); document.write( "\"A=pi%2A11%5E2\" Plug in \"r=11\" (see above)\r
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\n" ); document.write( "\n" ); document.write( "\"A=121pi\" Square 11 to get 121. Also, rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "So the exact area is \"121pi\" square milimeters.\r
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\n" ); document.write( "\n" ); document.write( "Note: because \"pi\" is irrational, we cannot write out the exact value of \"pi\". So we must leave it alone.\r
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\n" ); document.write( "\n" ); document.write( "Circumference:\r
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\n" ); document.write( "\n" ); document.write( "Remember, the circumference of a circle is \"C=2%2Ar%2Api\"\r
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\n" ); document.write( "\n" ); document.write( "\"C=2%2Ar%2Api\" Start with the given formula.\r
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\n" ); document.write( "\n" ); document.write( "\"C=2%2A11%2Api\" Plug in \"r=11\" (see above)\r
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\n" ); document.write( "\n" ); document.write( "\"C=22%2Api\" Multiply 2 and 11 to get 22\r
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\n" ); document.write( "\n" ); document.write( "So the exact circumference is \"22pi\" milimeters.\r
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\n" ); document.write( "\n" ); document.write( "# 7\r
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\n" ); document.write( "\n" ); document.write( "Note: since 10 mm = 1 cm, this means that 5 cm = 50 mm (just multiply both sides by 5)\r
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\n" ); document.write( "\n" ); document.write( "Since the diameter is 50 mm, this means that the radius is 25 mm (the radius is half the diameter)\r
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\n" ); document.write( "\n" ); document.write( "The formula for the volume of a cylinder is \"V=pi%2Ar%5E2%2Ah\"\r
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\n" ); document.write( "\n" ); document.write( "\"V=pi%2Ar%5E2%2Ah\" Start with the given formula.\r
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\n" ); document.write( "\n" ); document.write( "\"V=pi%2A25%5E2%2A140\" Plug in \"r=25\" and \"h=140\"\r
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\n" ); document.write( "\n" ); document.write( "\"V=pi%2A625%2A140\" Square 25 to get 625\r
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\n" ); document.write( "\n" ); document.write( "\"V=87500pi\" Multiply and rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"V=274889.356\" Replace \"pi\" with 3.14159265... and multiply. Note: this result is approximate\r
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\n" ); document.write( "\n" ); document.write( "So the glass can hold about 274,889.356 cubic milimeters.\r
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\n" ); document.write( "\n" ); document.write( "Now divide the result by 1000 to convert to convert to cubic centimeters to get:\r
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\n" ); document.write( "\n" ); document.write( "\"274889.356%2F1000=274.889\"\r
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\n" ); document.write( "\n" ); document.write( "Now round to the nearest tenth to get \"V=274.889\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the glass can hold about 274.9 cubic centimeters of water.\r
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\n" ); document.write( "\n" ); document.write( "# 8\r
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\n" ); document.write( "\n" ); document.write( "Here's some terminology:\r
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\n" ); document.write( "\n" ); document.write( "Vertex: A point representing a location (city, town, etc...). In general, what the vertex represents isn't important.\r
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\n" ); document.write( "\n" ); document.write( "Edge: A line connecting two vertices (plural for vertex)\r
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\n" ); document.write( "\n" ); document.write( "Odd Vertex: A vertex with an odd number of edges connecting to it\r
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\n" ); document.write( "\n" ); document.write( "Even Vertex: A vertex with an even number of edges connecting to it\r
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\n" ); document.write( "\n" ); document.write( "So here's one way to draw the graph:\r
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\n" ); document.write( "\n" ); document.write( "Vertex A: even vertex with 2 edges connecting to it\r
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\n" ); document.write( "\n" ); document.write( "Vertex B: odd vertex with 3 edges connecting to it\r
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\n" ); document.write( "\n" ); document.write( "Vertex C: even vertex with 2 edges connecting to it\r
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\n" ); document.write( "\n" ); document.write( "==============================================================================\r
\n" ); document.write( "\n" ); document.write( "# 9\r
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\n" ); document.write( "\n" ); document.write( "It is possible to travel through every door once (and only once) given that you either start in room F or end in room F (otherwise you can't do it).\r
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\n" ); document.write( "\n" ); document.write( "So here are 6 possible scenarios (there are possibly more)\r
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\n" ); document.write( "\n" ); document.write( "Scenario # 1:\r
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\n" ); document.write( "\n" ); document.write( "Scenario # 2:\r
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\n" ); document.write( "\n" ); document.write( "Scenario # 3:\r
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\n" ); document.write( "\n" ); document.write( "Scenario # 4:\r
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\n" ); document.write( "\n" ); document.write( "Scenario # 5:\r
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\n" ); document.write( "\n" ); document.write( "Scenario # 6:\r
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