document.write( "Question 193839: Two kids live 25 kilometers apart. They both leave their houses on bicycles at 9:00a.m. Kid 1 peddles 15 kilometers per hour, kid 2 peddles 12 kilometers per hour. What time will they meet? Please explain and show all steps.\r
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Algebra.Com's Answer #145538 by stanbon(75887)\"\" \"About 
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Two kids live 25 kilometers apart. They both leave their houses on bicycles at 9:00a.m. Kid 1 peddles 15 kilometers per hour, kid 2 peddles 12 kilometers per hour. What time will they meet? Please explain and show all steps.
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\n" ); document.write( "Kid 1 DATA:
\n" ); document.write( "rate = 15 km/h ; distance = x km ; time = d/r = x/15 hrs
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\n" ); document.write( "Kid 2 DATA:
\n" ); document.write( "rate = 12 km/h ; distance = (25-x) km ; time = d/r = (25-x)/12 hrs
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\n" ); document.write( "Equation:
\n" ); document.write( "time = time
\n" ); document.write( "x/15 = (25-x)/12
\n" ); document.write( "12x = 15(25-x)
\n" ); document.write( "27x = 15*25
\n" ); document.write( "x = 125/9 km
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\n" ); document.write( "Kid 1 time = x/15 = (125/9)/15 = 125/(9*15) = 0.926 hrs
\n" ); document.write( "0.926(60 minutes) = 59.56 minutes
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\n" ); document.write( "Ans: They will meet at 9:59 and 56 seconds or 10:00
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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