document.write( "Question 193839: Two kids live 25 kilometers apart. They both leave their houses on bicycles at 9:00a.m. Kid 1 peddles 15 kilometers per hour, kid 2 peddles 12 kilometers per hour. What time will they meet? Please explain and show all steps.\r
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Algebra.Com's Answer #145538 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Two kids live 25 kilometers apart. They both leave their houses on bicycles at 9:00a.m. Kid 1 peddles 15 kilometers per hour, kid 2 peddles 12 kilometers per hour. What time will they meet? Please explain and show all steps. \n" ); document.write( "thank you \n" ); document.write( "---------------------------- \n" ); document.write( "Kid 1 DATA: \n" ); document.write( "rate = 15 km/h ; distance = x km ; time = d/r = x/15 hrs \n" ); document.write( "-------------------------------------- \n" ); document.write( "Kid 2 DATA: \n" ); document.write( "rate = 12 km/h ; distance = (25-x) km ; time = d/r = (25-x)/12 hrs \n" ); document.write( "-------------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "time = time \n" ); document.write( "x/15 = (25-x)/12 \n" ); document.write( "12x = 15(25-x) \n" ); document.write( "27x = 15*25 \n" ); document.write( "x = 125/9 km \n" ); document.write( "------------------------------------ \n" ); document.write( "Kid 1 time = x/15 = (125/9)/15 = 125/(9*15) = 0.926 hrs \n" ); document.write( "0.926(60 minutes) = 59.56 minutes \n" ); document.write( "----------------------- \n" ); document.write( "Ans: They will meet at 9:59 and 56 seconds or 10:00 \n" ); document.write( "========================================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |