document.write( "Question 26655: Find the foci of the ellipse whose equation is (y^2/16) + (x^2/12) = 1 \n" ); document.write( "
Algebra.Com's Answer #14553 by venugopalramana(3286)\"\" \"About 
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Find the foci of the ellipse whose equation is (y^2/16)+(x^2/12)=1.
\n" ); document.write( "> COMPARING WITH STANDARD EQN. OF ELLIPSE
\n" ); document.write( "> (X^2/A^2)+(Y^2/B^2)+1...WE GET
\n" ); document.write( "> FOCI=(AE,0) AND (-AE,0)..WHERE E=SQRT.{(A^2-B^2)/A^2}
\n" ); document.write( "> WE HAVE A=4 AND E=SQRT.{(16-12)/16}=1/2..SO FOCI ARE..(2,0),(-2,0)
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