document.write( "Question 26655: Find the foci of the ellipse whose equation is (y^2/16) + (x^2/12) = 1 \n" ); document.write( "
Algebra.Com's Answer #14553 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! Find the foci of the ellipse whose equation is (y^2/16)+(x^2/12)=1. \n" ); document.write( "> COMPARING WITH STANDARD EQN. OF ELLIPSE \n" ); document.write( "> (X^2/A^2)+(Y^2/B^2)+1...WE GET \n" ); document.write( "> FOCI=(AE,0) AND (-AE,0)..WHERE E=SQRT.{(A^2-B^2)/A^2} \n" ); document.write( "> WE HAVE A=4 AND E=SQRT.{(16-12)/16}=1/2..SO FOCI ARE..(2,0),(-2,0) \n" ); document.write( " \n" ); document.write( " |