document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=193841>Question 193841</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Train A leaves the station traveling east at 45 mph. Three hours later train B leaves the same station traveling west at 55 mph. How long after train B leaves the station until the trains are 610 miles apart? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145525 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145525\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Train A leaves the station traveling east at 45 mph. Three hours later train B leaves the same station traveling west at 55 mph. How long after train B leaves the station until the trains are 610 miles apart?<BR>\n" );
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document.write( "Going opposite directions, their speeds relative to each other is the sum, 45+55 mph, = 100 mph.<BR>\n" );
document.write( "Train is 45*3 miles away = 135 miles.<BR>\n" );
document.write( "610 - 135 = 475 miles<BR>\n" );
document.write( "475/100 = 4.75 hours<BR>\n" );
document.write( "= 4 hours 45 minutes </SPAN>\n" );
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