document.write( "Question 193839: Two kids live 25 kilometers apart. They both leave their houses on bicycles at 9:00a.m. Kid 1 peddles 15 kilometers per hour, kid 2 peddles 12 kilometers per hour. What time will they meet? Please explain and show all steps.\r
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Algebra.Com's Answer #145524 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Considering the term 'kid' actually refers to the offspring of a goat, this is a rather interesting problem indeed. However, regardless of the actual organisms that are operating the bicycles, the answer is the same.\r
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\n" ); document.write( "\n" ); document.write( "Begin with:\r
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\n" ); document.write( "\n" ); document.write( "To describe the first one, you would say:\r
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\n" ); document.write( "\n" ); document.write( "Now the distance traveled by the second bicyclist is 25 minus the distance traveled by the first, so:\r
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\n" ); document.write( "\n" ); document.write( "Since we are ultimately concerned with the time that they meet, the time they traveled has to be the same for each of them.\r
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\n" ); document.write( "\n" ); document.write( "So solve each of the above equations for \r
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\n" ); document.write( "\n" ); document.write( "Since , we can set these two fractions equal to each other:\r
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\n" ); document.write( "\n" ); document.write( "Then cross-multiply:\r
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\n" ); document.write( "\n" ); document.write( "Which is the distance traveled by the first bicyclist.\r
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\n" ); document.write( "\n" ); document.write( "Since the first bicyclist's speed was 15 km/hr, the elapsed time must be:\r
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\n" ); document.write( "\n" ); document.write( " hours.\r
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\n" ); document.write( "\n" ); document.write( "Converting that to minutes and seconds to be added to the 9:00 AM start time is left as an exercise for the student.\r
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