document.write( "Question 26666: Solve the equation 25^(x+1)=125^x\r
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Algebra.Com's Answer #14547 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
LET 5^X=Y
\n" ); document.write( "> 25^X=(5^2)^X=5^2X=(5^X)^2=Y^2
\n" ); document.write( "> 125^X=(5^3)^X=5^3X=(5^X)^3=Y^3
\n" ); document.write( "WE HAVE....25^(X+1)=125^X...
\n" ); document.write( "(25^X)(25)=125^X...OR...
\n" ); document.write( "25Y^2=Y^3
\n" ); document.write( "Y^2(Y-25)=0...OR...Y=25..
\n" ); document.write( "5^X=25...SO..X=2
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