document.write( "Question 193776: A business invests $8,000 in a savings account for two years. At the beginning of the second year, an additional $2,500 is invested. At the end of the second year, the account balance is $11,445. What was the annual interest rate? \n" ); document.write( "
Algebra.Com's Answer #145466 by RAY100(1637) ![]() You can put this solution on YOUR website! assume simple interest ???????,,,I=PRT \n" ); document.write( ", \n" ); document.write( "yr,,,, invested,,,,,,interest,,,,,,invested,,,,,interest \n" ); document.write( "0,,,,,,8000 \n" ); document.write( "1,,,,,,,,,,,,,,,,,,,,,,, 8000R(1),,,,2500 \n" ); document.write( "2,,,,,,,,,,,,,,,,,,,,,,, 8000R(1),,,,,,,,,,,,,,,,,,, 2500R(1)\r \n" ); document.write( "\n" ); document.write( "total 8000 +2500+2*8000R +2500R =11,445 \n" ); document.write( ", \n" ); document.write( "10,500 + 16000R +2500R=11,445 \n" ); document.write( " 18500R=945 \n" ); document.write( "R= 945/18500 = .05108 = 5.108 % \n" ); document.write( ", \n" ); document.write( "check , 8000 + 2500 + 2*8000*.05108 + 2500* .0518 =11,445 \n" ); document.write( " |