document.write( "Question 193629: A tank contains 20 gallons of a 30% antifreeze solution. How many gallons of an 80% antifreeze solution shoul be added to the tank in order to have the concentration of the antifreeze in the tank increase to 50%? \n" ); document.write( "
Algebra.Com's Answer #145462 by checkley77(12844)\"\" \"About 
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.30*20+.80x=.5(20+x)
\n" ); document.write( "6+.8x=10+.5x
\n" ); document.write( ".8x-.5x=10-6
\n" ); document.write( ".3x=4
\n" ); document.write( "x=13.33 gal of 80% solution is needed.
\n" ); document.write( "Proof:
\n" ); document.write( ".30*20+.8*13.33=.5(20+13.33)
\n" ); document.write( "6+10.66=.5*33.33
\n" ); document.write( "16.66=16.66
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