document.write( "Question 26741: |3-x|=|x/2+3| \n" ); document.write( "
Algebra.Com's Answer #14544 by AnlytcPhil(1806)![]() ![]() You can put this solution on YOUR website! |3-x|=|x/2+3|\r\n" ); document.write( "\r\n" ); document.write( "There are two cases to consider.\r\n" ); document.write( "\r\n" ); document.write( "Case 1. What is within the absolute value bars on the left is equal to what is\r\n" ); document.write( " within the absolute value bars on the right.\r\n" ); document.write( " That is,\r\n" ); document.write( "\r\n" ); document.write( " 3 - x = x/2 + 3\r\n" ); document.write( "\r\n" ); document.write( "Case 2. What is within the absolute value bars on the left is equal to to the\r\n" ); document.write( " OPPOSITE of (-1 times) what is within the absolute value bars on the\r\n" ); document.write( " right. That is.\r\n" ); document.write( "\r\n" ); document.write( " 3 - x = -1(x/2 + 3) \r\n" ); document.write( "\r\n" ); document.write( "Case 1.\r\n" ); document.write( " 3 - x = x/2 + 3\r\n" ); document.write( "\r\n" ); document.write( "Solve that and get x = 0. That's one solution.\r\n" ); document.write( "\r\n" ); document.write( "Case 2.\r\n" ); document.write( " 3 - x = -1(x/2 + 3)\r\n" ); document.write( "\r\n" ); document.write( "Solve that and get x = 12. That's the other solution.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r\n" ); document.write( "AnlytcPhil@aol.com\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |