document.write( "Question 193741: I just found this website and I hope someone can help me with a real problem, problem.
\n" ); document.write( "In 1992 the life expectancy of males in a certain country was 72.5 yrs. In 1997, it was 75.3 yrs. Let e represent the life expectancy in year t and let t represent the number of years since 1992.
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Algebra.Com's Answer #145427 by RAY100(1637)\"\" \"About 
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Usually we assume \"exponential growth\"
\n" ); document.write( "This follows,,,y=C(1+r)^t,,,where C is initial amount,, r is rate,,and t is time
\n" ); document.write( "Using the given data
\n" ); document.write( "y(0) = C (1+r)^0 = 72.5
\n" ); document.write( "but as (1+r)^0 =1
\n" ); document.write( "C=72.5
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\n" ); document.write( "y(5) = 72.5 (1+r)^5 =75.3
\n" ); document.write( "(1+r)^5=75.3/72.5 = 1.03862
\n" ); document.write( "taking 5th root
\n" ); document.write( "(1+r) = 1.0076
\n" ); document.write( "r= .0076
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\n" ); document.write( "the general expression is
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\n" ); document.write( "e = 72.5 (1.0076) ^t
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