document.write( "Question 193743: Dorothy is 6 years older than Ricardo. The product of their present ages is twice what the product of their ages was 6 years ago. how old is Dorothy?
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Algebra.Com's Answer #145424 by user_dude2008(1862)\"\" \"About 
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\"Dorothy is 6 years older than Ricardo.\" -----> d=r+6\r
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\n" ); document.write( "\n" ); document.write( "\"The product of their present ages is twice what the product of their ages was 6 years ago\" ----> d*r=2(d-6)(r-6)\r
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\n" ); document.write( "\n" ); document.write( "d*r=2(d-6)(r-6)\r
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\n" ); document.write( "\n" ); document.write( "(r+6)*r=2(r+6-6)(r-6)\r
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\n" ); document.write( "\n" ); document.write( "(r+6)*r=2r(r-6)\r
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\n" ); document.write( "\n" ); document.write( "r+6=2(r-6)\r
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\n" ); document.write( "\n" ); document.write( "r+6=2r-12\r
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\n" ); document.write( "\n" ); document.write( "6+12=2r-r\r
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\n" ); document.write( "\n" ); document.write( "18=r\r
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\n" ); document.write( "\n" ); document.write( "r=18 ----> Ricardo is 18 yrs old\r
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\n" ); document.write( "\n" ); document.write( "d=r+6=18+6=24 ----> Dorothy is 24 yrs old\r
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