document.write( "Question 193743: Dorothy is 6 years older than Ricardo. The product of their present ages is twice what the product of their ages was 6 years ago. how old is Dorothy?
\n" );
document.write( "I have trued to find something similar in the section of word problem and just totally confused myself- HELP PLEASE! \n" );
document.write( "
Algebra.Com's Answer #145424 by user_dude2008(1862)![]() ![]() ![]() You can put this solution on YOUR website! \"Dorothy is 6 years older than Ricardo.\" -----> d=r+6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"The product of their present ages is twice what the product of their ages was 6 years ago\" ----> d*r=2(d-6)(r-6)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "d*r=2(d-6)(r-6)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(r+6)*r=2(r+6-6)(r-6)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(r+6)*r=2r(r-6)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "r+6=2(r-6)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "r+6=2r-12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6+12=2r-r\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "18=r\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "r=18 ----> Ricardo is 18 yrs old\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "d=r+6=18+6=24 ----> Dorothy is 24 yrs old\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |