document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=193738>Question 193738</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if -1/3x+7=16, what is the value of 2x+1? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145410 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145410\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (-1/3)x+7=16\r<BR>\n" );
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document.write( "(-1/3)x=16-7\r<BR>\n" );
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document.write( "(-1/3)x=9\r<BR>\n" );
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document.write( "x=9(-3)\r<BR>\n" );
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document.write( "x=-27\r<BR>\n" );
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document.write( "---> 2x+1 = 2(-27)+1 = -54 + 1 = -53\r<BR>\n" );
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document.write( "Ans: 2x+1 = -53 </SPAN>\n" );
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