document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=193704>Question 193704</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to calculate the formular as below :<BR>\n" );
document.write( "1). 2X+3Y=21<BR>\n" );
document.write( "2). X/2+Y/3=19/6\r<BR>\n" );
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document.write( "Pls help me to find out the best way to solve the problem, TQ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145378 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145378\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> remember  three  ways  to  solve  linear  equations,  1)  graph,  2) substitution,  3)elimination<BR>\n" );
document.write( "on  this  one  let's  try  elimination<BR>\n" );
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document.write( "1)  2x+3y=21<BR>\n" );
document.write( "2)  x/2+y/3=19/6<BR>\n" );
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document.write( "to  eliminate  fractions  let's  multiply  (2)  by  6<BR>\n" );
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document.write( "2a)  3x  +2y  =19<BR>\n" );
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document.write( "Comparing  1)  and  2a),  we  might  multiply,  1) by  3,,and  2a)  by  2,, to  get  common  coefficients<BR>\n" );
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document.write( "1)    6x  +9y =63<BR>\n" );
document.write( "2a)  6x  +4y =38<BR>\n" );
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document.write( "Now  let's  subtract  1)-2a)<BR>\n" );
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document.write( "5y=25<BR>\n" );
document.write( "y=5,,,,,ANSWER<BR>\n" );
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document.write( "substitute  into  1)<BR>\n" );
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document.write( "2x+3(5)=21<BR>\n" );
document.write( "2x=21-15=6<BR>\n" );
document.write( "x=3,,,,,,ANSWER<BR>\n" );
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document.write( "checking<BR>\n" );
document.write( "1)  2(3)+3(5)=21<BR>\n" );
document.write( "6+15=21,,,ok<BR>\n" );
document.write( "2)  (3)/2  +(5)3 = 19/6<BR>\n" );
document.write( "1.5+1.667=3.167<BR>\n" );
document.write( "3.167=3.167  ,,,ok </SPAN>\n" );
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