document.write( "Question 193657: The lifetime of a certain brand of battery is known to have a standard deviation of 10.5 hours. Suppose that a random sample of 120 such batteries has a mean lifetime of 40.9 hours. Based on this sample, find the 95% confidence interval for the true mean lifetime of all batteries of this brand.\r
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Algebra.Com's Answer #145353 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The lifetime of a certain brand of battery is known to have a standard deviation of 10.5 hours. Suppose that a random sample of 120 such batteries has a mean lifetime of 40.9 hours. Based on this sample, find the 95% confidence interval for the true mean lifetime of all batteries of this brand. \n" ); document.write( "---------------------------------------- \n" ); document.write( "x-bar = 40.9 hours ; s = 10.5 \n" ); document.write( "-------------------- \n" ); document.write( "E = 1.96*10.5/sqrt(120) = 1.8787 \n" ); document.write( "---------------------------------------- \n" ); document.write( "95% C.I: 40.9 - 1.8787 < u < 40.9 + 1.8787 \n" ); document.write( "95% C.I.: 39.02 < u < 42.78 \n" ); document.write( "================================ \n" ); document.write( "Comment: Some texts require you to use a t-distribution \n" ); document.write( "when calculating \"mean\" C.I.'s and working Hypothesis tests. \n" ); document.write( "If you use \"t\" to get your E value you get: \n" ); document.write( "95% C.I.: 39.002 < p < 42.798 \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |