document.write( "Question 193653: log(x+1)+log(x-2)=1 \n" ); document.write( "

Algebra.Com's Answer #145345 by Alan3354(69443) $\"\"$ $\"About$

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log(x+1)+log(x-2)=1
\n" ); document.write( "------------
\n" ); document.write( "log((x+1)*(x-2)) = 1
\n" ); document.write( "(x+1)*(x-2) = 10
\n" ); document.write( " $\"x%5E2+-+x+-+2+=+10\"$
\n" ); document.write( " $\"x%5E2+-+x+-+12+=+0\"$
\n" ); document.write( "(x-4)*(x+3) = 0
\n" ); document.write( "x = 4
\n" ); document.write( "x = -3
\n" ); document.write( " \n" ); document.write( "

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