document.write( "Question 193641: Could you please show me how to solve this: \"3+-%28a-5%29%2F%28a%2B5%29+=+%28a%5E2-15%29%2F%28a%2B5%29+\"\r
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Algebra.Com's Answer #145335 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for a:
\n" ); document.write( "\"3-%28%28a-5%29%2F%28a%2B5%29%29+=+%28a%5E2-15%29%2F%28a%2B5%29\" Simplify the left side.
\n" ); document.write( "\"%283%28a%2B5%29-%28a-5%29%29%2F%28a%2B5%29+=+%28a%5E2-15%29%2F%28a%2B5%29\"
\n" ); document.write( "\"%283a%2B15-a%2B5%29%2F%28a%2B5%29+=+%28a%5E2-15%29%2F%28a%2B5%29\"
\n" ); document.write( "\"%282a%2B20%29%2F%28a%2B5%29+=+%28a%5E2-15%29%2F%28a%2B5%29\" Multiply both sides by (a+5).
\n" ); document.write( "\"2a%2B20+=+a%5E2-15\" Rearrange this to form a quadratic equation in standard form.
\n" ); document.write( "\"a%5E2-2a-35+=+0\" Factor.
\n" ); document.write( "\"%28a-7%29%28a%2B5%29+=+0\"
\n" ); document.write( "\"a+=+7\" or \"a+=+-5\" But...if we substitute a = -5 into the original equation then we have division by zero which, of course, is a no-no! So a = -5 is and excluded solution.
\n" ); document.write( "The acceptable solution is:
\n" ); document.write( "\"highlight%28a+=+7%29\"
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