document.write( "Question 193524: Joe has a collection of nickels and dimes that is worth $6.05. If the number of dimes was doubled and the number of nickels was decreased by 10, the value of the coins would be $9.85. How many dimes does he have?\r
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Algebra.Com's Answer #145332 by ankor@dixie-net.com(22740)\"\" \"About 
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Joe has a collection of nickels and dimes that is worth $6.05.
\n" ); document.write( "If the number of dimes was doubled and the number of nickels was decreased by 10,
\n" ); document.write( " the value of the coins would be $9.85.
\n" ); document.write( " How many dimes does he have?
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\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "\"Joe has a collection of nickels and dimes that is worth $6.05.\"
\n" ); document.write( ".05n + .10d = 6.05
\n" ); document.write( ":
\n" ); document.write( "\"If the number of dimes was doubled and the number of nickels was decreased by
\n" ); document.write( " 10, the value of the coins would be $9.85.\"
\n" ); document.write( ".05(n-10) + .10(2d) = 9.85
\n" ); document.write( ".05n - .50 + .20d = 9.85
\n" ); document.write( ".05n + .20d = 9.85 + .50
\n" ); document.write( ".05n + .20d = 10.35
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\n" ); document.write( "Subtract the 1st equation from the above:
\n" ); document.write( ".05n + .20d = 10.35
\n" ); document.write( ".05n + .10d = 6.05
\n" ); document.write( "---------------------Subtraction eliminates n find d
\n" ); document.write( ".10d = 4.30
\n" ); document.write( "d = \"4.3%2F.1\"
\n" ); document.write( "d = 43 dimes is what he has
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\n" ); document.write( "That's the answer they want, but to check the problem we have to find n
\n" ); document.write( ".05n + .10(43) = 6.05
\n" ); document.write( ".05n + 4.30 = 6.05
\n" ); document.write( ".05n = 6.05 - 4.30
\n" ); document.write( ".05n = 1.75
\n" ); document.write( "n = \"1.75%2F.05\"
\n" ); document.write( "n = 35 dimes
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\n" ); document.write( "Check solution in the 2nd equation
\n" ); document.write( ".05(n-10) + .10(2d) =
\n" ); document.write( ".05(25) + .10(86) =
\n" ); document.write( "1.25 + 8.60 = 9.85; confirms out solution of 43 dimes
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