document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=193595>Question 193595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs to have a 70% acid solution. He has 5 gallons of a 90% acid solution. How much pure water must be added to the 90% acid solution to obtain the 70% acid solution he requires? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145308 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145308\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  A chemist needs to have a 70% acid solution. He has 5 gallons of a 90% acid solution. How much pure water must be added to the 90% acid solution to obtain the 70% acid solution he requires?<BR>\n" );
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document.write( "5 gal of 90% --> 4.5 gals of acid (the rest water)<BR>\n" );
document.write( "For the 4.5 gal of acid to be 70% of the solution, the total amount of liquid is 4.5/0.7 = 45/7<BR>\n" );
document.write( "5 gals is 35/7 so 10/7 gallons of water has to be added. </SPAN>\n" );
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