document.write( "Question 193510: A rectangular garden has dimensions of 15 feet by 11 feet. A gravel path of uniform width is to be built around the garden. How wide can the path be if there is enough gravel for 192 square feet? \r
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Algebra.Com's Answer #145293 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
15*11+192=(15+2x)(11+2x)
\n" ); document.write( "165+192=165+22x+30x+4x^2
\n" ); document.write( "4x^2+52x-192=0
\n" ); document.write( "4(x^2+13x-48)=0
\n" ); document.write( "4(x+16)(x-3)=0
\n" ); document.write( "x-3=0
\n" ); document.write( "x=3 ft. is the width of the path.
\n" ); document.write( "Proof:
\n" ); document.write( "15*11+192=(15+6)(11+6)
\n" ); document.write( "165+192=21*17
\n" ); document.write( "357=357\r
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