document.write( "Question 193510: A rectangular garden has dimensions of 15 feet by 11 feet. A gravel path of uniform width is to be built around the garden. How wide can the path be if there is enough gravel for 192 square feet? \r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #145293 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 15*11+192=(15+2x)(11+2x) \n" ); document.write( "165+192=165+22x+30x+4x^2 \n" ); document.write( "4x^2+52x-192=0 \n" ); document.write( "4(x^2+13x-48)=0 \n" ); document.write( "4(x+16)(x-3)=0 \n" ); document.write( "x-3=0 \n" ); document.write( "x=3 ft. is the width of the path. \n" ); document.write( "Proof: \n" ); document.write( "15*11+192=(15+6)(11+6) \n" ); document.write( "165+192=21*17 \n" ); document.write( "357=357\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |