document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=193541>Question 193541</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you please provide me with a detailed explanation on how to solve the following...\r<BR>\n" );
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document.write( "log2 (5) - log2 (15) + log2 (24) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145282 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145282\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log2 (5) - log2 (15) + log2 (24)<BR>\n" );
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document.write( "logs are exponents.<BR>\n" );
document.write( "When you subtract exponents you are dividing some numbers<BR>\n" );
document.write( "When you add exponents you are multiplying some numbers<BR>\n" );
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document.write( "Your problem involves subtracting (divide) and adding (multiply):<BR>\n" );
document.write( "= logc [5*24/15]<BR>\n" );
document.write( "= log2 [8]<BR>\n" );
document.write( "= 3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "Ask, if you do not understand.<BR>\n" );
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document.write( " </SPAN>\n" );
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