document.write( "Question 193537This question is from textbook
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document.write( ": A heavy metal sphere with radius 10 cm is dropped into a
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document.write( "right circular cylinder with base radius of 10 cm. If the
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document.write( "original cylinder has water in it that is 20 cm high, how
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document.write( "high is the water after the sphere is placed in it?\r
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document.write( "I do not understand how to solve this. Please help. Thank you. \n" );
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Algebra.Com's Answer #145278 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! here is a URL for volume --> http://math.about.com/od/formulas/ss/surfaceareavol.htm\r \n" ); document.write( "\n" ); document.write( "Let's think about this first. \n" ); document.write( "We have a sphere that will sink in the water. \n" ); document.write( "The cylinder is wide enough to contain the sphere. (one could argue that a sphere with radius 10 won't fit into a cylinder with radius 10. But we will let that one go for now)\r \n" ); document.write( "\n" ); document.write( "When we drop the sphere into the cylinder of water, it sinks to the bottom.\r \n" ); document.write( "\n" ); document.write( "How much water is displaced by the sphere we dropped in?\r \n" ); document.write( "\n" ); document.write( "The volume of a sphere is given by \n" ); document.write( "\n" ); document.write( "So we know how much water is displaced.\r \n" ); document.write( "\n" ); document.write( "Now that we know the amount of water that 'moved', and we know the container holding that water is a right circular cylinder, all we need to know is the formula for the volume of such a cylinder.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we can equate those two volumes and solve for h \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We are told r = 10 , so that yields |