document.write( "Question 193531This question is from textbook algebra and trigonometry structure and method book 2
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document.write( ": Find the vertex, focus, directrix, and axis of symmetry of each parabola.
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document.write( "x^2+8y+4x-4=0
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document.write( "We have been using the formulas y-k=a(x-h)^2 and x-h=a(y-k)^2 I don't understand which to use here, even after completing the square and its confusing because I don't know which is which. please explain and be specific. thank you. \n" );
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Algebra.Com's Answer #145268 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "a=coefficient of \n" ); document.write( ": \n" ); document.write( "so vertex is (-2,0) \n" ); document.write( "focus is (-2,0+1/4a)-->1/4a=1/(4(-1/8)=1/(-1/2)=-2--> (-2,-2) \n" ); document.write( ": \n" ); document.write( "directrix is at y=-1/4a=-1/4(-1/8)=-1/(-1/2)=2 so y=2 \n" ); document.write( ": \n" ); document.write( "axis of symmetry is x=-2 \n" ); document.write( ": \n" ); document.write( " |